Q1 . 10 years ago the elder sibling was twice the age of the younger sibling,10 years later their ages were in the ratio of 6:5.Find their current ages?

1. 10 and 20

2. 15 and 20

3. 15 and 30

4. 25 and 20

Check Answer

Correct Answer is

15 and 20

SOLUTION

let the current age of younger sibling be y and older one be y

so ,10 years back ages would be x-10=2(y-10)

After 10 years , x+10/y+10=6/5

solving both the equation we sould get x=20 and y=15

or after forming equations just put the values from options

Q2 . A couple got married 15 years ago,then their ages were in the ratio 5:4.Ten year later from the current day their ages are in the ratio of 10:9.Find their current ages?

1. 25 and 40

2. 30 and 40

3. 35 and 40

4. 20 and 40

Check Answer

Correct Answer is

35 and 40

SOLUTION

Let the current ages of couple be X and Y

15 years back their ages are x-15/y-15=5/4

10 years later their ages will be in the ratio x+10/y+10=10/9

solving the equations we get current ages as 35 and 40

or after forming equations just put the values from options

Q3 . A father is 3 times as old as his son 5 years back.After 5 years the fathers ageis in the ratio 5:3.Find the current ages ?

1. 10 and 25

2. 12 and 20

3. 14 and 20

4. 10 and 20

Check Answer

Correct Answer is

10 and 20

SOLUTION

let their current ages be x and y

so 5 years back it would have been x-5=3(y-5)

After 5 years it would be x+5/y+5=3/5 since we have taken the sons age as x and father as y

solving the equation we will get their ages as 10 and 20

Q4 . The sum of the ages of mother and father 5 years back was 12 times the age of the son.After 5 years the son is 15 years old.Find the sum of the ages of parents?

1. 70 years

2. 72 years

3. 60 years

4. 100 years

Check Answer

Correct Answer is

70 years

SOLUTION

If after 5 years son is 15 years old then current age is 10 and 5 years back it was 5 years old

5 years back it was 12 times 5 so 60

current sum of ages is 60+5+5=70 years

we add 5 two times as both their ages will increase by 5 each.

Q5 . There are two siblings.After ten years the age of one sibling is twice the other siblings age.find their current ages?

1. 20 and 10

2. 11and 10

3. 0 and 10

4. 12 and 10

Check Answer

Correct Answer is

0 and 10

SOLUTION

after 10 years age of one is twice the other

so 10 years should be the age of the elder one as plus 10 will double the age

so ages are 0 and 10 years

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Age solved problems part -1

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