AGE SOLVED PROBLEMS 1

1. 10 and 20

2. 15 and 20

3. 15 and 30

4. 25 and 20

15 and 20

let the current age of younger sibling be y and older one be y

so ,10 years back ages would be x-10=2(y-10)

After 10 years , x+10/y+10=6/5

solving both the equation we sould get x=20 and y=15

or after forming equations just put the values from options

1. 25 and 40

2. 30 and 40

3. 35 and 40

4. 20 and 40

35 and 40

Let the current ages of couple be X and Y

15 years back their ages are x-15/y-15=5/4

10 years later their ages will be in the ratio x+10/y+10=10/9

solving the equations we get current ages as 35 and 40

or after forming equations just put the values from options

1. 10 and 25

2. 12 and 20

3. 14 and 20

4. 10 and 20

10 and 20

let their current ages be x and y

so 5 years back it would have been x-5=3(y-5)

After 5 years it would be x+5/y+5=3/5 since we have taken the sons age as x and father as y

solving the equation we will get their ages as 10 and 20

1. 70 years

2. 72 years

3. 60 years

4. 100 years

70 years

If after 5 years son is 15 years old then current age is 10 and 5 years back it was 5 years old

5 years back it was 12 times 5 so 60

current sum of ages is 60+5+5=70 years

we add 5 two times as both their ages will increase by 5 each.

1. 20 and 10

2. 11and 10

3. 0 and 10

4. 12 and 10

0 and 10

after 10 years age of one is twice the other

so 10 years should be the age of the elder one as plus 10 will double the age

so ages are 0 and 10 years

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