Q1 . A couple had a child 3 years after their marriage.They had their second child at twice the interval they had their first child from marriage.At what time from the marriage did they have their second child?
1. 6 years
2. 7 years
3. 8 years
4. 9 years
Correct Answer is
9 years
SOLUTION
they had their first child after 3 years
second child after 3x2 =6 years
total time is 6+3=9
They had second child after 9 years
Q2 . The age difference between two siblings is 5 years.After ten years the sum of their ages is 4 less than 65 years.Find their current ages?
1. 24 and 18
2. 23 and 18
3. 22 and 18
4. 24 and 18
Correct Answer is
23 and 18
SOLUTION
let the current age of one be x and the other be x-5
after 10 years it will be (x+10)+(x-5+10)=61
so solving we will get x=23
so the other would be 18 years
Q3 . The current age difference between two friends is 15 years. 5 years before the age of the older friend is 3 less than twice the age of his younger friend.Find their current ages?
1. 32 and 23
2. 38 and 23
3. 48 and 23
4. 46 and 23
Correct Answer is
38 and 23
SOLUTION
let the current ages be x and x-15
5 years back it would have been x-5=2(x-15-5)-3
solving we would get x=38 and the other one would be 38-15=23
Q4 . A man and wife got married 10 years ago then their ages were in the ratio 5:7.Ten years after the current date their ages are in the ratio 9:11?
1. 30 and 45
2. 33 and 45
3. 25 and 45
4. 35 and 45
Correct Answer is
35 and 45
SOLUTION
Let the current ages be x and y
10 years ago it would have been x-10/y-10=5/7 and
after ten years it would be x+10/y+10=9/11
solving we get ages as 35 and 45
Q5 . A couple had a child every 5 years after marriage.When the man was 60 years old he had is 5th child.At what age did they get married?